more documentation of similarities and avoiding them where practicable.

This commit is contained in:
Paul Gardner-Stephen committed 2019-04-24 16:13:24 +09:30
1 parent 035b386f6c
commit 7448909da8
17 files changed
+161 -12

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CLC / ADC #40 / STA $nn
Add 40 to a ZP location. No creativity here.
Effectivelhy only one insstruction.
Not copyrightable.
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string "BASIC "
Since we are writing a BASIC language interprettor, such a string is expected.
BASIC appears in many other works. It cannot be copyrighted as a word.
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String "BASIC V2"
As we are implementing a V2 class BASIC interprettor, it is
natural for us to include this string.
There are many BASIC intreprettors, and the word cannot be
copyrighted, nor it is reasonable to contemplate that a party
could be constrained from having a BASIC with version 2, or
displaying that information anywhere. Not copyrightable.
+7
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RTS + LDA $028D
RTS is a very common instruction, as is loading A from absolute address.
The RTS is the end of a routine, and the LDA $028D thus the start of
another. Thus this would occur whenever a routine begins with loading
A from $028D, immediately after another routine. Nothing creative.
Not copyrightable.
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Something with $0277 / INX
Only one whole instruction here. Not copyrightable.
+3
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something with $0286 / STA ($F3),Y
Only one whole instruction. Not copyrightable.
+44
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Copy screen + colour RAM to the right one place
This sequence of instructions:
loop:
DEY
LDA ($D1),Y
INY
STA ($D1),Y
DEY
LDA ($F3),Y
INY
STA ($F3),Y
DEY
CPY $D3
BNE loop
LDA #$20
STA ($D1),Y
is the obvious any minimal way to copy the screen and colour RAM data.
The constants $D1 and $F3 are fixed by the publicly documented interface
of the KERNAL to point to the screen and colour RAM of the screen.
The Y register is the only register that can be used to post-increment an
indirect address on the 6502.
Thus the only efficient manner to copy a string to the right one byte
is to read, increment Y by one to get the destination address, store,
then decrement Y again so that it points to the source offset, now read
the colour RAM byte, add one to Y so that we point to the destination,
and then write it.
Similarly the check against $D3 (current column of cursor on screen) is also
necessary for working out when to terminate the loop. The storing of $20
into the screen RAM is also required to effect the insertion of a space.
In fact, about the only variant possible would be to swap the $D1 and $F3
constants so that the colour RAM is copied before the screen RAM in each
loop, instead of after it.
It is telling that this routine was the result of independent implementation
of this routine, without looking at the KERNALs routine, in terms of supporting
the argument that the routine is the obvious manner in which to do this.
+44
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Copy screen + colour RAM to the right one place
This sequence of instructions:
loop:
DEY
LDA ($D1),Y
INY
STA ($D1),Y
DEY
LDA ($F3),Y
INY
STA ($F3),Y
DEY
CPY $D3
BNE loop
LDA #$20
STA ($D1),Y
is the obvious any minimal way to copy the screen and colour RAM data.
The constants $D1 and $F3 are fixed by the publicly documented interface
of the KERNAL to point to the screen and colour RAM of the screen.
The Y register is the only register that can be used to post-increment an
indirect address on the 6502.
Thus the only efficient manner to copy a string to the right one byte
is to read, increment Y by one to get the destination address, store,
then decrement Y again so that it points to the source offset, now read
the colour RAM byte, add one to Y so that we point to the destination,
and then write it.
Similarly the check against $D3 (current column of cursor on screen) is also
necessary for working out when to terminate the loop. The storing of $20
into the screen RAM is also required to effect the insertion of a space.
In fact, about the only variant possible would be to swap the $D1 and $F3
constants so that the colour RAM is copied before the screen RAM in each
loop, instead of after it.
It is telling that this routine was the result of independent implementation
of this routine, without looking at the KERNALs routine, in terms of supporting
the argument that the routine is the obvious manner in which to do this.
+4
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something with $028D / CMP #$03 / BNE somewhere
Only one whole instruction. Nothing creative.
Not copyrightable.
+1
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STA $028C / LDA #$0E / STA $0286 / LDA
+3
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Use X register to compare contents of a ZP and absolute address location
Nothing copyrightable here in this simple comparison of memory contents.
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LDA ($D1),Y / CMP #$20
Compare a byte read from a pointer with a specific value.
No creativity here. Not copyrightable.
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Fragment / CMP #$11 / BNE somewhere
Only one whole intruction here. Not copyrightable.
+3
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Fragment / CMP #$13 / BNE somewhere
Only one whole intruction here. Not copyrightable.